[Python] 2.7 Encoding 에러 해결

• 파이썬 2.7 인코딩 에러 해결

(UnicodeDecodeError: 'ascii' codec can't decode byte 0xc7 in position 0: ordinal)

스크립트 첫줄에 파일의 인코딩을 명시

#-*- coding: utf-8 -*- 

• C:\Python27\Lib\site.py
  • Encoding utf-8 수정

def setencoding():     """Set the string encoding used by the Unicode implementation.  The     default is 'ascii', but if you're willing to experiment, you can     change this."""     encoding = "utf-8" # Default value set by _PyUnicode_Init() # 요기!     if 0:         # Enable to support locale aware default string encodings.         import locale         loc = locale.getdefaultlocale()         if loc[1]:             encoding = loc[1]     if 0:         # Enable to switch off string to Unicode coercion and implicit         # Unicode to string conversion.         encoding = "undefined"     if encoding != "utf-8":  # 요기!         # On Non-Unicode builds this will raise an AttributeError...         sys.setdefaultencoding(encoding) # Needs Python Unicode build ! 

• C:\Python27\Lib\ntpath.py
  • ***p_path를 p_path.encode('utf-8')로 치환해준다.***

....     elif p_drive and p_drive != result_drive:         if p_drive.lower() != result_drive.lower():             # Different drives => ignore the first path entirely             result_drive = p_drive             result_path = p_path             continue         # Same drive in different case         result_drive = p_drive     # Second path is relative to the first     if result_path and result_path[-1] not in '\\\\/':         result_path = result_path + '\\\\'     result_path = result_path + p_path.encode('utf-8')  # 요기! ## add separator between UNC and non-absolute path if (result_path and result_path[0] not in '\\\\/' and     result_drive and result_drive[-1:] != ':'):     return result_drive + sep + result_path return result_drive + result_pat